![]() ![]() This voltage is sensed with reference to the other pin of the IC (pin16) which is internally fixed at a reference voltage of 5.1V. The term error amplifier itself suggests that the opamp is assigned to sense and check a feedback sample voltage (error signal) from the inverter output and correct the output PWM width accordingly. Pin1 of IC SG3525/3524 actually forms one of the pinouts of the internal error amplifier opamp. Pin1 is the sensing input of the IC which responds and makes the PWMs narrower whenever the fed voltage from the 100k pot exceeds a certain predetermined limit. It rectifies and sends a sample feedback voltage from the inverter mains output to pin1 of the IC which identifies this feedback and accordingly controls the PWM of the IC and regulates it so that the output from the inverter never exceeds a predetermined limit as set by the 100k preset. The section that's circled is a simple bridge rectifier with a potential divider stage in the form of a 100k pot. The drawing of the circuit was turned upside down by the computer operators I gave it to. Can you help me please The section I circled with a pen is the part of the circuit I do not really understand anything about it. He listed the parts but building the circuit is not easy for me as there is one section I do not really understand what that IC represents. ![]() ![]() Our Lecturer gave us the schematic on a printed sheet to build the circuit on our own. Sir, I would need your help on a project about a schematic that I do not understand a particular section. ![]()
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